Digital Electronics: Statement Problems (Part 1)
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- Geetika Gogoi: Ans: A
- Koustav Ghosh: the answer is A
- Muhammad Muzakkir Azad: Y=A.B+AB'C+AB'C' Y=AB+AB'(C+C') Y=AB+AB' Y=A(B+B') Y= A
- gyaneshwar singh: see..nothing is said about A ..so if u really want to write A as well..then u have to write like...A'BC+ABC..(bcoz both the conditions are possible..A can be high as well as A can be low)..now if you take BC as common..you will get the same result..ok...hope it helps.
- Phani Shadrak: Y= (A.B)+AB’C+AB’C’ Y= A.B+AB’[C+C’] Y=A.B+AB’.1 Y=A[B+B’] Y=A
- Hemanth Kumar: thanks for your videos. answer is A
- Nishchal Joshi: Y=A
- Nithin Bairi: a & b are true a & c are true and b is false a is true and b & c are false a.b ab'c ab'c' y=ab+ab'c+ab'c' y=ab+ab'(c+c') y=ab+ab'=>a y=a
- tarandeep singh: Y=A
- ABHISHEK KUMAR: Y=A.B + AB'C + AB'C' = AB + AB'(C+C') = AB+AB'(1) = AB+AB' = A(B+B') =A
- Krishna Chaitanya: Moon Celine ABC+A'B'C' may or may not be equal to 1. Actually ABC+(ABC)' equals 1. Hope you got it!
- jyeshtar sou: Y=A+B'
- shubhankar tripathi: A
- anant ranjan: ANS
- Vishalbagda: Y=A
- Charan Guggulla: Y=A
- amir ansari: y=A
- Esha Kaparvwan: Y=A
- richa bhardwaj: Y=A ( answer) and thank u so much😊
- Prabu Krish: the answer is A.
- Neso Academy: +Hemanth Kumar Welcome!
- suman saurabh: great video series ans A
- anjali anand: Y= A
- Nikhil Raj: Answer: Y=A
- Shubham kumar: Sir as given in Q1) 1st condition that B&C are true that means A must be false than why we are not taking(A'BC)
- harshit kumar: why we have used or for adding all conditions
- Krishna Jangir: Y=A
- Neso Academy: +Attila Lőcsei Welcome!
- Thrimurthi M: Ankita Goyal# No how do you got??
- Shubham kumar: And sir if I'm taking like this than I'M getting answer as(A'B+BC+A'C')
- Shreyash Wagh: Y=A
- Ashish Jain: The ans is Y = A
- Attila Lőcsei: Y = A . Great series of videos. You go deeper into details than my actuall teacher. Thanks
- Ashlesh Khajbage: Y=A...ANS
- saiakhilesh sanaboyina: thank you neso
- pasupuleti pasupuleti: y=A
- Kapish Blog: Y=A
- Mir Muneer Hussain " I am a Change ": Answer is : A ...... :-)
- Saurabh Kumar: Y=A
- Prashant Mishra: Y = A
- umar shafiq: Y=A
- Lakshman Patel: Y=A.B+AB'C+AB'C' Y=AB+AB'(C+C') Y=AB+AB' Y=A(B+B') Y=A
- rushikesh bute: A
- Karan Chauhan: but why did you or them why didnt you and them
- Celine Moon: Regarding the first question, Y= BC + A'C' + ABC + A'B'C' : for the last two terms, ABC + A'B'C' equals 1 which would make Y = 1 . How come Y is minimized as BC + A'C' ??
- Prabu Krish: Y = AB + AB'C + AB'C' = AB + AB'(C+C') = AB + AB' = A(B+B') = A ----> ANS
- Danish Bhatia: A
- Roshan Maharana: Y=A
- pradeep kumar: A
- Sanah Hassan: A is the answer...
- Sahil Tarkase: Yes
- lokesh amara: Y=A
- S P PRAVEEN: ans:- A
- deepak pandey: Because the function f=1 on given conditions that means its SOP ( sum of products method). And if f =0 on this conditions then its POS method
- Arijit Roy: A
- The CRAZY PHOTON: A
- Asma Jaan: its Y=A
- Nitika Sharma: Y=A
- Danish Bhatia: bro, video me '&' use hua hai ' and ' nahi
- Harsh Asati: Y = A
- Ankita: If we make the truth table, we can see that condition (i) & (ii) are contradictory
- ankit agarwal: y=A is the answer
- anant ranjan: A
- Sahil Tarkase: Thanks for these Video Tommorow is my exam A is the answer
- ashok chatla: Y=A
- Simrat Saini: Y=A is the answer
- pushmit gupta: Y=A
- Soumyajit Gayen: AB+AB'
- ashok chatla: Thank you so much sir
- Nikith TN: A
- gottimukkala jaswanth: y=A
- Neera Rajput: A
- Hasnain Sarfaraz: A
Statement Problems in Boolean Algebra (Part 1) | |
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| Education | Upload TimePublished on 19 Oct 2015 |
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